Cambridge IGCSE (9–1) Physics 0972 (Extended) (2026–2028) · 4.2.4

Resistance Flashcards – Cambridge IGCSE (9–1) Physics 0972 (Extended) (2026–2028)

Revise Cambridge IGCSE (9–1) Physics 0972 (Extended) (2026–2028) specification point 4.2.4, Resistance, with free active-recall flashcards. Flip through the set or review every question and answer below.

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Cards in this set (9)

What equation relates resistance RR to potential difference VV and current II?

R=VIR = \frac{V}{I}

What are the units of resistance, potential difference and current?

  • Resistance: ohms (Ω\Omega)
  • Potential difference: volts (V)
  • Current: amperes (A)

How can the resistance equation be rearranged to calculate potential difference VV or current II?

V=IRV = IR and I=VRI = \frac{V}{R}

For what conditions does a resistance calculated from voltage and current apply?

The conditions under which the voltage and current were measured.

With a power supply connected, how should an ammeter and voltmeter be connected to measure a component’s resistance?

Connect the ammeter in series with the component and the voltmeter in parallel across it.

How is resistance in ohms calculated from potential difference in volts and current in amperes?

R=VIR = \frac{V}{I}

What condition must the current and potential difference readings satisfy when calculating a component’s resistance?

They must refer to the same operating conditions.

How does the length of a metallic wire affect its resistance when material, temperature and cross-sectional area are held constant?

A longer wire has greater resistance.

How does the cross-sectional area of a metallic wire affect its resistance when material, temperature and length are held constant?

A larger cross-sectional area gives lower resistance.