Capacitance (A-level only)

AQA·Physics·3.7.4.1

Capacitance

A capacitor stores charge on two plates. The plates carry equal and opposite charges: if one plate has charge $$+Q$$, the other has charge $$-Q$$. There is a potential difference $$V$$ between the plates.

Capacitance measures how much charge is stored per unit potential difference across the capacitor:

C=QVC = \frac{Q}{V}

Here, $$C$$ is the capacitance, $$Q$$ is the magnitude of the charge on either plate, and $$V$$ is the potential difference between the plates. For the same potential difference, a capacitor with a greater capacitance stores more charge on each plate.

For a capacitor whose capacitance is constant, rearranging the relationship gives:

Q=CVQ = CV

The stored charge is therefore directly proportional to the potential difference: doubling $$V$$ doubles $$Q$$.

The SI unit of capacitance is the farad ($$\mathrm{F}$$). One farad is one coulomb per volt: $$1,\mathrm{F} = 1,\mathrm{C},\mathrm{V}^{-1}$$.

Capacitance (A-level only) | AQA A-level Physics (7408) Revision Notes | KnowledgeSet